In a trapezium abcd if ab cd then ac2 + bd2
WebIn a trapezium ABCD If AB∥CD, thee AC2+BD2is equal to: A BC2+AD2+2AB.CD B AB2+CD2+2AD.BC C AB2+CD2+2AB.CD D BC2+AD2+2BC.AD Viewed by: 529students Solutions (1) (a): In ΔABD,∠A is acute. So BD2=AD2+ AB2−2AB.AQ ---(i) In ΔABC,∠B is acute. WebABCD is a trapezium in which AB is parallel to CD. If ∠A=36 ∘ and ∠B=81 ∘, then find ∠C and ∠D. Medium View solution > Suppose ABCD is a trapezium in which AB∥CD and AD=BC. Prove that ∠A=∠B and ∠C=∠D. Medium View solution > View more More From Chapter Understanding Quadrilaterals View chapter > Revise with Concepts
In a trapezium abcd if ab cd then ac2 + bd2
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WebTo prove : AC2+BD2 = AD2+BC2. Construction : Produce AB and CD to meet at E. Also, join AC and BD. Proof : In ΔAED, ∠A+∠D= 90∘ [given] ∴ ∠E= 180∘−(∠A+∠D) = 90∘ [because sum of all angles in a triangle= 180∘] Then, by using Pythagoras theorem, WebIn trapezium ABCD, AB CD. Consider right angled Δ BEC: ⇒ BC2 = BE2+EC2 →By using PythagorasTheorem. Similarly, in right angled Δ BED ⇒ BD2 = BE2+DE2. By above …
Web1 In ABC and DEF ∠B = ∠E, ∠F = ∠C and AB = 3DE then which of the statements regarding the two triangles is true? a. The triangles are not congruent and not similar WebDec 13, 2024 · Answer 1 person found it helpful deepali019930 ABCD is a trapezium such that AB and CD are parallel and BC⊥CD. If ∠ADB=θ, BC=p and CD=q, then AB is equal to cosα= p 2 +q 2 q and sinα= p 2 +q 2 p Using sine rule in triangle ABD sinθ AB = sin (θ+α) BD ⇒AB= sinθcosα+cosθsinα p 2 +q 2 sinθ = p 2 +q 2 sinθ⋅q + p 2 +q 2 cosθ⋅p p 2 +q 2 sinθ …
WebFeb 19, 2012 · In a trapezium ABCD , if AB ll CD , then (AC2 - BD2 )= (i) BC2 + AD2 + 2BC x AD (ii) AB2 + CD2 + 2AB x BC (iii) AB2 + CD2 + 2AD x BC (iv) BC2 + AD2 + 2AB x CD - … WebClass - 9th MathsChapter-8, QuadrilateralsExercise- 8.1, Q12ABCD is a trapezium in which AB CD andAD = BC (see Fig. 8.23). Show that(i)∠ A = ∠ B(ii)∠ C = ...
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WebFeb 26, 2024 · In the latter case AC and BD would be two sides. Use the cosine rule in traingles ABC, ACD, ABD and BCD: AC2=AB2+BC2−2AB\timesBCcosB , … phobia of pillowsWebSolution Verified by Toppr Correct option is D) In the triangle BCD cosα= p 2+q 2q and sinα= p 2+q 2p Using sine rule in triangle ABD sinθAB= sin(θ+α)BD ⇒AB= sinθcosα+cosθsinα p 2+q 2sinθ = p 2+q 2sinθ⋅q+ p 2+q 2cosθ⋅pp 2+q 2sinθ ⇒AB= (pcosθ+qsinθ)(p 2+q 2)sinθ Video Explanation Was this answer helpful? 0 0 phobia of phones ringingWebDec 12, 2024 · The length of the parallel sides of a trapezium are 14 cm and 7 cm. If the length of third side is 8 cm and of fourth side is x cm , then the number of possible integral values of x are 12 phobia of picklesWebDec 13, 2024 · ABCD is a trapezium such that AB and CD are parallel and BC⊥CD. If ∠ADB=θ, BC=p and CD=q, then AB is equal to. cosα= p . 2 +q . 2. q. and sinα= p . 2 +q . 2. p. Using … phobia of pimplesWebFeb 7, 2024 · Trapezium Question Download Solution PDF In a trapezium ABCD, AB is parallel to DC. The diagonals AC and BD intersect at P. If AP ∶ PC = 4 ∶ (4x - 4) and BP ∶ PD = (2x - 1) ∶ (2x + 4), then what is the value of x? This question was previously asked in CDS Maths Previous Paper 11 (Held On: 7 Feb 2024) Attempt Online View all CDS Papers > 4 3 … tswinga postal codeWebIn a right triangle PQR, if PR 2+PQ 2=QR 2 , then the angle equal to 90 o. ABCD is rhombus. Prove that AC 2+BD 2=4AB 2. phobia of photos of yourselfWebMar 26, 2024 · Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site phobia of phones