Show that 12n cannot end with the digit 0
WebIf 12n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12n contains the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. ⇒ 12n = (22 × … WebShow that 12 n cannot end with the digit 0 or 5 for any natural number n. Answers (1) We know that, if any number ends up with digit 0 or 5 then it must be divisible by 5. Here 12n …
Show that 12n cannot end with the digit 0
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WebMar 19, 2024 · Show that 12n cannot end with the digit 0 or 5 for any natural number n. Viewed by: 5,029 students Updated on: Mar 19, 2024 1 student asked the same question on Filo Learn from their 1-to-1 discussion with Filo tutors. 3 mins Uploaded on: 3/19/2024 Taught by Adarsh Tiwari Connect instantly with this tutor Connect now WebNov 27, 2024 · Solution: If the number 12n, for any natural number n, ends with the digit 0 or 5, then it is divisible by 5. That is, the prime factorization of 12n contains the prime 5. This …
WebShow that (12) n cannot end with digit 0 or 5 for any natural number n. Answers (1) There is no factor of the form 5 n, therefore, 12 n can not end with digit 0 or 5 for any natural … WebApr 19, 2013 · Now, 3^n will never have 0 at the one's digit and the same is true for 4^n. So, 12^n can never end with digit 0 for any natural number n. Answered by 19 Apr, 2013, 07:02: PM
WebIf 12 n ends with the digit zero or five it should be divisible by 5. It is possible if prime factorisation of 12 n has the prime number 5. 12 = 2 × 2 × 3 = 22 × 3. 12 n = (22 × 3) n = 22 … WebIf 12 n ends with the digit zero it must be divisible by 5. This is possible only if prime factorisation of 12 n contains the prime number 5. Now, 12 = 2 × 2 × 3 = 2 2 × 3 ⇒ 12 n = …
WebApr 25, 2024 · Show that 12 n cannot end with the digit 0 or 5 for any natural number n. Solution: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12 n ends with the digit zero or five it must be divisible by 5. This is possible only if prime factorisation of 12 n contains the prime number 5. Now, 12 = 2 x 2 x 3 = 2 2 x 3 12 n = (2 2 ...
WebSolution Verified by Toppr If 6 n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6 n should contain the prime number 2 and 5. But it is not possible because 6 n=2 n∗3 n so … the neighbourhood - scary loveWebToppr the neighbour online subtitratWebApr 6, 2024 · Best answer As we know that 15n = (3 x 5)n = 3n x 5n The prime factorization of 15 doesn't have a 2 and 5 as its factor. So, its factorization will never end in 10 as a number ending in 10 must have a factors as 5 and 2. So, 15n will never end in zero as 15 doesn't has 2 as a factor. ← Prev Question Next Question → Find MCQs & Mock Test michael toschlog new paris ohioWebApr 9, 2024 · EXAMPLE 5 Show that 1 2 n cannot en SOLUTION Expressing 12 as the product of primes, we obtain 12 ⇒ 1 2 n = 2 2 × 3 = (2 2 × 3) n = (2 2) n × 3 n = (2) 2 n × 3 n So, only primes in the factorisation of 1 2 n are 2 and 3 and, not 5 . Hence, 1 2 n cannot end with digit 0 or 5. LEVEL-2 EXAMPLE 6 Show that thereare infinitely many positive ... michael torpey wikiWebJul 31, 2024 · Answer: 12^n cannot end with digit 0 or 5 Step-by-step explanation:12^n has multiples= 2×2×3. Since the multiples of 12 do not contain 5 therefore it cannot end with 0 or5 This is because if any no. Is ending with 5 then it must have atleast one 5 in its multiples and if any no. Ends with 0 then it must have a pair of 5&2 as its multiples the neighbors tv show cancelledWebJun 11, 2024 · Answer: If any number ends with the digit 0 or 5, it is always divisible by 5. If 12n ends with the digit zero it must be divisible by 5. This is possible only if prime … the neighbors zac efron castWebApr 2, 2012 · Now , For 12 n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12 n cannot end with the digit 0 or 5. Hope it helps!! This conversation is already closed by Expert Was this answer helpful? 208 View Full Answer michael torka